- Định lý Simpson và tỷ lệ thể tích - Có lời giải...

A \(\dfrac{{{V_{S.A'B'C'}}}}{{{V_{S.ABC}}}} = \dfrac{1}{3}.\dfrac{{SA'}}{{SA}}.\dfrac{{SB'}}{{SB}}.\dfrac{{SC'}}{{SC}}\)

B \(\dfrac{{{V_{S.A'B'C'}}}}{{{V_{S.ABC}}}} = \dfrac{{SA'}}{{SA}}.\dfrac{{SB'}}{{SB}}.\dfrac{{SC'}}{{SC}}\)

C \(\dfrac{{{V_{S.A'B'C'}}}}{{{V_{S.ABC}}}} = \dfrac{{SA}}{{SA'}}.\dfrac{{SB}}{{SB'}}.\dfrac{{SC}}{{SC'}}\)

D \(\dfrac{{{V_{S.A'B'C'}}}}{{{V_{S.ABC}}}} = \dfrac{1}{3}.\dfrac{{SA}}{{SA'}}.\dfrac{{SB}}{{SB'}}.\dfrac{{SC}}{{SC'}}\)

A 4/3

B 1/4

C 4

D 3/4

A 8/3

B 1/4

C 4

D 3/8