BTVN - Hàm số lượng giác (Tiết 2) - Có lời giải ch...

A \(\mathbb{R}\)

B \(\left[ { - 1;0} \right]\)            

C \(\left[ { - 2;2} \right]\)

D \(\left[ { - 1;1} \right]\)

A \(\left[ {0;1} \right]\)

B \(\left[ {2;3} \right]\)

C \(\left[ { - 2;3} \right]\)

D \(\left[ {1;5} \right]\)

A \(0\)      

B \( - 1\)

C \(1\)      

D \( - 2\)

A \(\left[ { - 1;1} \right]\) 

B \(\left[ {0;1} \right]\)

C \(\left[ { - 1;0} \right]\)

D \(\left[ { - 1;3} \right]\)

A \( - 2\)

B \( - 1\)

C \(\dfrac{1}{2}\)

D \(1\)

A \(\mathbb{R}\)

B \(\left[ { - 1;1} \right]\)

C \(\left[ { - 2;2} \right]\)

D \(\left[ { - \sqrt 2 ;\sqrt 2 } \right]\)

A \(\sqrt 2 \)         

B \(2\)      

C \(\sqrt 3 \)

D \(1\)

A \(\left[ -7;7 \right]\)

B \(\left[ -3;3 \right]\)

C \(\left[ -4;4 \right]\)

D \(\left[ -5;5 \right]\)

A \(2\)      

B \( - 1\)

C \(\sqrt 3 \)

D \(1\)

A \(\left[ {4;8} \right]\)

B \(\left[ {0;1} \right]\)

C \(\left[ {3;5} \right]\)

D \(\mathbb{R}\)

A \(2\)      

B \(1\)      

C \(5\)      

D \(3\)

A \(\left[ { - 3;3} \right]\)

B \(\left[ {\dfrac{3}{4};3} \right]\)        

C \(\left[ {1;4} \right]\)

D \(\mathbb{R}\)

A \(1\)

B \(3\)

C \(4\)

D \(5\)

A \(T =  - 2\pi .\)

B \(T = \dfrac{\pi }{2}.\)

C

\(T = \pi .\)

D \(T = 2\pi .\)

A \(T = \pi .\)

B \(T = 2\pi .\)

C \(T = 4\pi .\)

D \(T = {\pi ^2}.\)

A \(T = \pi .\)       

B \(T = 2\pi .\)

C \(T = 4\pi .\)

D \(T = 4{\pi ^2}.\)

A \(T = 2\pi .\)

B \(T = 4\pi .\)

C \(T = \pi .\)       

D \(T = 3\pi .\)

A \(T = \dfrac{\pi }{2}.\)

B \(T = \pi .\)       

C \(T = \dfrac{{3\pi }}{2}.\)      

D \(T = 2\pi .\)

A \(T=\pi .\)

B \(T=\dfrac{2\pi }{3}.\)

C \(T=2\pi .\)      

D \(T=3\pi .\)

A \(\left( { - 6\pi ; - 5\pi } \right)\)

B \(\left( {\dfrac{{19\pi }}{2};10\pi } \right)\)

C \(\left( { - \dfrac{{7\pi }}{2}; - 3\pi } \right)\)

D \(\left( {7\pi ;\dfrac{{15\pi }}{2}} \right)\)

A \(\left( {\dfrac{\pi }{6} + k\pi ;\dfrac{{2\pi }}{3} + k\pi } \right)\,\,\left( {k \in \mathbb{Z}} \right)\)

B

\(\left( {\dfrac{{5\pi }}{{12}} + k\pi ;\dfrac{{11\pi }}{{12}} + k\pi } \right)\,\,\left( {k \in \mathbb{Z}} \right)\)

C \(\left( { - \dfrac{\pi }{3} + k\pi ;\dfrac{\pi }{6} + k\pi } \right)\,\,\left( {k \in \mathbb{Z}} \right)\)

D \(\left( { - \dfrac{\pi }{6} + k\pi ;\dfrac{{5\pi }}{6} + k\pi } \right)\,\,\left( {k \in \mathbb{Z}} \right)\)

A \(y = \sin \left( { - \dfrac{x}{2}} \right)\)

B \(y = \sin \dfrac{x}{2}\)

C \(y = \sin \dfrac{x}{4}\)

D \(y = \cos \dfrac{x}{2}\)

A \(y = \sqrt 2 \sin \left( {x - \dfrac{\pi }{6}} \right)\)

B \(y = \cos \left( {x - \dfrac{{3\pi }}{4}} \right)\)

C \(y = \sin \left( {x - \dfrac{{3\pi }}{4}} \right)\)

D \(y = \cos \left( {x - \dfrac{\pi }{4}} \right)\)

A \(y =  - \sqrt 2 \sin \left( {x - \dfrac{\pi }{4}} \right)\)

B \(y = \sqrt 2 \sin \left( {x + \dfrac{\pi }{4}} \right)\)

C \(y = \sqrt 2 \sin \left( {x - \dfrac{{3\pi }}{4}} \right)\)          

D \(y = \sqrt 2 \cos \left( {x - \dfrac{\pi }{4}} \right)\)

A

\(y = \cos x\)

B

\(y = \left| {\cos x} \right|\)

C \(y =  - \cos x\)

D \(y = \cos 2x\)