Trắc nghiệm Toán 11 Bài 2 Phương trình lượng giác...

A. $x = \frac{\pi }{{20}} + k\frac{\pi }{2};x = \frac{\pi }{5} + k\frac{\pi }{2},k \in \mathbb{Z}.$    

B. $x = \frac{\pi }{{20}} + k\frac{\pi }{2};x = \frac{\pi }{{10}} + k\frac{\pi }{2},k \in \mathbb{Z}.$

C. $x = \frac{\pi }{{10}} + k\frac{\pi }{2};x = \frac{\pi }{5} + k\frac{\pi }{2},k \in \mathbb{Z}.$

D. $x = \frac{{3\pi }}{5} + k\frac{\pi }{2};x = \frac{\pi }{{10}} + k\frac{\pi }{2},k \in \mathbb{Z}.$

A. $x =  \pm \arccos \frac{2}{5} - \frac{\pi }{{18}} + k2\pi ,k \in \mathbb{Z}.$

B. $x =  \pm \arccos \frac{2}{5} + \frac{\pi }{{18}} + k2\pi ,k \in \mathbb{Z}.$

C. $x =  \pm \arccos \frac{5}{2} - \frac{\pi }{{18}} + k2\pi ,k \in \mathbb{Z}.$

D. $x =  \pm \arccos \frac{5}{2} + \frac{\pi }{{18}} + k2\pi ,k \in \mathbb{Z}.$

A. ${x_1} = 5 - \frac{{11\pi }}{6};{x_2} = 5 - \frac{{13\pi }}{6}.$

B. ${x_1} = 5 + \frac{{11\pi }}{6};{x_2} = 5 - \frac{{13\pi }}{6}.$

C. ${x_1} = 5 - \frac{{11\pi }}{6};{x_2} = 5 + \frac{{13\pi }}{6}.$

D. ${x_1} = 5 + \frac{{11\pi }}{6};{x_2} = 5 + \frac{{13\pi }}{6}.$

A. $x = \frac{{3\pi }}{5} + k\pi ,k \in \mathbb{Z}.$

B. $x = \frac{\pi }{5} + k\pi ,k \in \mathbb{Z}.$

C. $x = \frac{{3\pi }}{5} + \frac{{k\pi }}{3},k \in \mathbb{Z}.$

D. $x = \frac{\pi }{5} + \frac{{k\pi }}{3},k \in \mathbb{Z}.$

A. $x =  - \frac{1}{6} + k\frac{\pi }{2},k \in \mathbb{Z}.$

B. $x =  - \frac{1}{3} + k\frac{\pi }{2},k \in \mathbb{Z}.$

C. $x =  - \frac{1}{6} + k\pi ,k \in \mathbb{Z}.$

D. $x =  - \frac{1}{3} + k\pi ,k \in \mathbb{Z}.$

A. $x =  - {200^0} + k{360^0},k \in \mathbb{Z}.$

B. $x =  - {200^0} + k{720^0},k \in \mathbb{Z}.$

C. $x =  - {20^0} + k{360^0},k \in \mathbb{Z}.$

D. $x =  - {20^0} + k{720^0},k \in \mathbb{Z}.$

A. $x = \frac{{7\pi }}{{18}} + \frac{{k2\pi }}{3};x = \frac{{7\pi }}{6} + k2\pi ,k \in \mathbb{Z}.$

B. $x =  - \frac{{7\pi }}{{18}} + \frac{{k2\pi }}{3};x = \frac{{7\pi }}{6} + k2\pi ,k \in \mathbb{Z}.$

C. $x =  - \frac{{7\pi }}{{18}} + \frac{{k2\pi }}{3};x =  - \frac{{7\pi }}{6} + k2\pi ,k \in \mathbb{Z}.$

D. $x = \frac{{7\pi }}{{18}} + \frac{{k2\pi }}{3};x =  - \frac{{7\pi }}{6} + k2\pi ,k \in \mathbb{Z}.$

A. 262

B. 266

C. 281

D. 292