Đề thi học kì 1 - Toán 7 Trường Amsterdam - Năm họ...

A a) \( - \frac{{20}}{6}.\)

b) \(4\)

B a) \(  \frac{{20}}{3}.\)

b) \(\frac{{5}}{3}\)

C a) \( - \frac{{25}}{3}.\)

b) \(-2\)

D a) \( - \frac{{20}}{3}.\)

b) \(2\)

A a)\(x = 8\) hoặc \(x = \frac{8}{3}.\)

b) \(x \in \left\{ { - 3; - \frac{1}{2};\,\,3} \right\}.\)

c) \(x \in \left\{ {\frac{{3\sqrt 3 }}{2};\frac{{\sqrt 3 }}{2}} \right\}.\)

d) \(x = \frac{{1012}}{{1011}}.\)

B a)\(x = 8\) hoặc \(x = \frac{8}{5}.\)

b) \(x \in \left\{ { - 3; - \frac{1}{4};\,\,3} \right\}.\)

c) \(x \in \left\{ {\frac{{3\sqrt 3 }}{2};\frac{{\sqrt 3 }}{4}} \right\}.\)

d) \(x = \frac{{1011}}{{1012}}.\)

C a)\(x = 6\) hoặc \(x = \frac{8}{3}.\)

b) \(x \in \left\{ {  3; - \frac{1}{2};\,\,3} \right\}.\)

c) \(x \in \left\{ {\frac{{2\sqrt 3 }}{2};\frac{{\sqrt 3 }}{2}} \right\}.\)

d) \(x = \frac{{1010}}{{1011}}.\)

D a)\(x = 4\) hoặc \(x = \frac{8}{3}.\)

b) \(x \in \left\{ { - 3; - \frac{1}{2};\,\,-3} \right\}.\)

c) \(x \in \left\{ {\frac{{3\sqrt 2 }}{2};\frac{{\sqrt 5 }}{2}} \right\}.\)

d) \(x = \frac{{1001}}{{1011}}.\)