\(\,B = \frac{{\left( {\frac{{{8^2}}}{{128}} + \fr...

Câu hỏi: \(\,B = \frac{{\left( {\frac{{{8^2}}}{{128}} + \frac{3}{4}} \right):1\frac{3}{{16}}}}{{1\frac{{11}}{{19}}}}\)

A \(\frac{2}{3}\)

B \(\frac{-2}{3}\)

C \(\frac{1}{3}\)

D \(\frac{-1}{3}\)